Unsupported Inherited Field Error

Description

This error is thrown when a strawberry.pydantic.input inherits a field with a default factory from a Strawberry input type, for example the following code will throw this error:

import pydantic
import strawberry
 
 
@strawberry.input
class Pagination:
    tags: list[str] | None = strawberry.field(default_factory=list)
 
 
@strawberry.pydantic.input
class SearchInput(pydantic.BaseModel, Pagination):
    query: str

This happens because Strawberry types are dataclasses, which don't keep a field's default factory on the class. Pydantic doesn't see the factory, so the field would be required by Pydantic and the factory would never be used.

The same error is thrown when a strawberry.pydantic type inherits a field with a resolver, like label: str = strawberry.field(resolver=get_label) , from a regular Strawberry type or interface. Pydantic sees the annotation of the field, and makes it a field of the model, with the resolver as its default value, so the model would return the function as the value of label .

How to fix this error

You can fix this error by declaring the field with its default factory on the Pydantic model:

import pydantic
import strawberry
 
 
@strawberry.pydantic.input
class SearchInput(pydantic.BaseModel):
    query: str
    tags: list[str] | None = pydantic.Field(default_factory=list)

Declare fields with a resolver as methods with @strawberry.field , which Pydantic doesn’t see, so the model inherits them like any other method:

import pydantic
import strawberry
 
 
def get_label() -> str:
    return "Label"
 
 
@strawberry.interface
class Labelled:
    @strawberry.field
    def label(self) -> str:
        return get_label()
 
 
@strawberry.pydantic.type
class Product(pydantic.BaseModel, Labelled):
    name: str

You can also declare the interface with @strawberry.pydantic.interface , and the field with @strawberry.pydantic.field .